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Fix description of the R6RS `finite?' in manual

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* doc/ref/r6rs.texi (rnrs base): `(finite? x)' returns true iff x is
  neither infinite nor a NaN.  Previously, it stated that `finite?' was
  the negation of `infinite?', which was incorrect because NaNs are
  neither finite nor infinite.  Combine description of 'nan?' with those
  of `finite?' and `infinite?'.
This commit is contained in:
Mark H Weaver 2011-03-01 12:37:01 -05:00
parent 73ea546c51
commit 4f1bbedb6d
1 changed files with 8 additions and 5 deletions
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13
doc/ref/r6rs.texi
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@ -356,7 +356,6 @@ grouped below by the existing manual sections to which they correspond.
@deffn {Scheme Procedure} real? x
@deffnx {Scheme Procedure} rational? x
@deffnx {Scheme Procedure} nan? x
@deffnx {Scheme Procedure} numerator x
@deffnx {Scheme Procedure} denominator x
@deffnx {Scheme Procedure} rationalize x eps
@ -542,11 +541,15 @@ loss of numerical precision.
imaginary parts are zero.
@end deffn
@deffn {Scheme Procedure} finite? x
@deffn {Scheme Procedure} nan? x
@deffnx {Scheme Procedure} infinite? x
@code{infinite?} returns @code{#t} if @var{x} is an infinite value,
@code{#f} otherwise. @code{finite?} returns the negation of
@code{infinite?}.
@deffnx {Scheme Procedure} finite? x
@code{nan?} returns @code{#t} if @var{x} is a NaN value, @code{#f}
otherwise. @code{infinite?} returns @code{#t} if @var{x} is an infinite
value, @code{#f} otherwise. @code{finite?} returns @code{#t} if @var{x}
is neither infinite nor a NaN value, otherwise it returns @code{#f}.
Every real number satisfies exactly one of these predicates. An
exception is raised if @var{x} is not real.
@end deffn
@deffn {Scheme Syntax} assert expr